A forum for discussing and organizing recreational softball and baseball games and leagues in the greater Halifax area.
Come on guys...
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I thought that was the d8. At least the 4 is flared at the base
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The math checks out, but the problem is the danger of rolling a nat 20 on your practice roll. The odds of getting two nat 20s in a row are almost as low as the odds of getting two nat 1s, so you may be screwing yourself out of a crit
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I think the problem is that people forget *Monty Hall* has information that the contestant does not. The naive assumption is that he's just picking a door and you're just picking a door. The unsophisticated viewer never really stops to think about why Monty Hall never points to a door and reveals a prize by mistake. One way I've had success explaining it is to expand the problem to more than three doors. Assume 100 doors. Monty Hall then says "Open 98 doors" and fails to reveal a prize behind any of them. Now its a bit more clear that he knows something you don't.
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Gosh it's almost like I was joking or something
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I have a character that started with 14 12 10 8 4 3. He is my only character that hasn't been downed, and he is religiously restricted suicidal. He is a 910 year old dwarf who has a guaranteed place in Elysium*. He just cant die of old age. *Terms and conditions apply.
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The trick is to say "this is just a practice roll" where the die can hear you, but wink at the GM so they know it's the real roll. That way, the die will be a spiteful little punk and throw out the nat20 for the "practice". But don't do that too often, or the die will figure out the trick.And when the Nat 1 shows up, rub your eye because you had sand in it.
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Weirdly enough, it’s just the way probability works. Once something stops being a possibility, and becomes a fact (ie. dice are rolled, numbers known) - future probability is no longer affected (assuming independent events like die rolls). e.g. you have a 1/400 chance of rolling two 1s on a D20 back-to-back. But if your first roll is a 1, you’re back down to the standard 1/20 chance of doing it again - because one of the conditions has already been met.That's very interesting to me (I am a bit mathematically illiterate when it comes to probability). Wouldn't it still have a lower chance of being a 1 if you said you want your second roll to be the one that counts beforehand? Or would different permutations screw with the odds, say rolling a 12 then a 1, rolling a 15 and a 1, etc, counting towards unfavourable possibilities and bringing it back to 1/20?
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That's very interesting to me (I am a bit mathematically illiterate when it comes to probability). Wouldn't it still have a lower chance of being a 1 if you said you want your second roll to be the one that counts beforehand? Or would different permutations screw with the odds, say rolling a 12 then a 1, rolling a 15 and a 1, etc, counting towards unfavourable possibilities and bringing it back to 1/20?Because the outcome of a dice roll is an independent event (ie. the outcome of any given event does not impact subsequent events), it doesn’t matter if you said only your 2nd/3rd/4th etc. roll counted. Every roll has a 1/20 chance of rolling a 1 on a D20 die. Consider this thought experiment, there are ~60.5m people, each rolling a 6-sided die. Only the people who roll a 6 can continue to the next round, and the game continues until there is only 1 winner. After the first roll, only ~10m people remain in the game. After the second roll, ~1.7m people remain After the third roll, ~280K After the fourth, ~46.5K 5th, ~7.8K 6th, ~1.3K 7th, ~216 8th, ~36 9th, ~6 After the 10th and final roll, there should only be ~1 player remaining. So even though initially there is only a 1-in-65m chance of rolling 10 6s back-to-back initially, each attempt still has a 1/6 chance of succeeding. By the time we get down to the final six contestants, they have each rolled a 6 nine times in a row - yet their chances of rolling it another time is still 1/6.
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The thing you're getting by switching is the benefit of the information provided by the person who revealed an empty door. Before a door is open, you have a 1/3 chance of selecting correctly. After you select a door, the host picks from the other two doors. This provides extra information you didn't have during your initial selection. The host points to a door *they know is a dud* and asks for it to open. So now you're left with the question "Did I pick the correct door on the first go? Or did the host skip the door that had the prize?" There's a 1/3 chance you picked the right door initially and a 2/3 chance the host had to avoid the prize-door.
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That’s stupid. But obviously how the dice strikes the table impacts its balance and therefore the probability of rolling specific numbers. So we must figure out what side need to strike the table first to decrease the probability of getting an undesirable roll. Boom, I out physicsed you’re probabilities.
